One mole of 1,2-dibromopropane on treatment with X moles of NaNH2 followed by treatment with ethyl bromide gave a pentyne. The value of X is
Question
Solution 1
The reaction of 1,2-dibromopropane with NaNH2 results in the formation of a terminal alkyne through a process known as double dehydrohalogenation.
Here are the steps:
- The first mole of NaNH2 (sodium amide) removes a hydrogen and a bromine atom from 1,2-dibromopropane, resulting in the formatio Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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