Rohan was 4 times as old as his son 6 years ago.After 6 years Rohan will be twice as old as his son.What is son's present age?10 years12 years14 years18 years
Question
Rohan was 4 times as old as his son 6 years ago.
After 6 years Rohan will be twice as old as his son.
What is son's present age?
- 10 years
- 12 years
- 14 years
- 18 years
Solution
Let's denote Rohan's present age as R and his son's present age as S.
From the problem, we know that:
-
Rohan was 4 times as old as his son 6 years ago. This can be written as: R - 6 = 4 * (S - 6)
-
After 6 years, Rohan will be twice as old as his son. This can be written as: R + 6 = 2 * (S + 6)
Now we can solve these two equations to find the values of R and S.
From the first equation, we can express R in terms of S: R = 4S - 18
Substitute R in the second equation: 4S - 18 + 6 = 2S + 12
Simplify the equation: 2S = 24
So, S = 12
Therefore, Rohan's son is currently 12 years old.
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