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What is the sum of the interior angles of a 10-sided regular polygon?Question 10Select one:a.1,800°b.360°c.1,004°d.1,440°

Question

What is the sum of the interior angles of a 10-sided regular polygon?

Select one:

a. 1,800°
b. 360°
c. 1,004°
d. 1,440°

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Solution

Step 1: Break Down the Problem

To find the sum of the interior angles of a polygon, we use the formula: Sum of interior angles=(n2)×180° \text{Sum of interior angles} = (n - 2) \times 180° where n n is the number of sides of the polygon. In this case, we have a 10-sided polygon (decagon).

Step 2: Relevant Concepts

Using the formula provided, we can plug in the value of n n :

  • n=10 n = 10

Step 3: Analysis and Detail

Now we can calculate the sum of the interior angles: Sum of interior angles=(102)×180° \text{Sum of interior angles} = (10 - 2) \times 180° =8×180° = 8 \times 180° =1440° = 1440°

Step 4: Verify and Summarize

The calculation states that the sum of the interior angles of a 10-sided polygon is indeed 1440° 1440° .

Final Answer

Thus, the sum of the interior angles of a 10-sided regular polygon is 1,440° \mathbf{1,440°} (Option d).

This problem has been solved

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