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A 107 digit number is formed by writing first 58 natural numbers next to each other. Find the remainder when number is divided by 8.

Question

A 107 digit number is formed by writing first 58 natural numbers next to each other. Find the remainder when number is divided by 8.

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Solution

The problem is asking for the remainder when a 107-digit number, formed by writing the first 58 natural numbers next to each other, is divided by 8.

To solve this problem, we need to understand that when a number is divided by 8, the remainder is determined by the last three digits of the number. This is because 8 divides 1000, so the remainder when any number is divided by 8 is the same as the remainder when the last three digits of that number are divided by 8.

The first 58 natural numbers are: 1, 2, 3, ..., 58. When we write these numbers next to each other, we get a 107-digit number. The last three digits of this number are the last three digits of 58, which are 058.

So, we need to find the remainder when 58 is divided by 8.

58 divided by 8 is 7 remainder 2.

Therefore, the remainder when the 107-digit number is divided by 8 is 2.

This problem has been solved

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