A party program has four dances, two talk shows, three chorus, dance programs can not appear in a row, how many kinds of order of the program?

First, let's consider the dances as a single unit. So, we have 3 units: dances, talk shows, and chorus.

These 3 units can be arranged in 3! = 321 = 6 ways.

Within the dance unit, the 4 dances can be arranged in 4! = 432*1 = 24 ways.

However, since the dance programs cannot appear in a row, we need to place the other programs (talk shows and chorus) between them.

Consider the 4 dances as D1, D2, D3, D4 and the other programs as X. We can arrange them like this: D1 - X - D2 - X - D3 - X - D4.

There are 3 slots for the other programs (talk shows and chorus) between the dances. The 5 other programs (2 talk shows and 3 chorus) can be arranged in these 3 slots in 5P3 ways.

5P3 = 5! / (5-3)! = 543 = 60 ways.

So, the total number of ways to arrange the program is 6 (ways to arrange the units) * 24 (ways to arrange the dances within the dance unit) * 60 (ways to arrange the other programs between the dances) = 8640 ways.