The two bodies A and B are placed in space. The body A exerts a force of 20 N on B for 6 s. What would be the impulse on B by A?

1. Break Down the Problem

To find the impulse on body B due to the force exerted by body A, we will use the formula for impulse, which is the product of force and the time duration for which the force is applied.

2. Relevant Concepts

The concept of impulse can be expressed mathematically as: $\text{Impulse} = F \times \Delta t$ where:

• $F$ is the force applied (in Newtons),
• $\Delta t$ is the time duration (in seconds).

3. Analysis and Detail

Given:

• $F = 20 \, \text{N}$
• $\Delta t = 6 \, \text{s}$

Now, substituting the given values into the impulse formula: $\text{Impulse} = 20 \, \text{N} \times 6 \, \text{s}$

4. Verify and Summarize

Calculating the impulse: $\text{Impulse} = 120 \, \text{N·s}$

Final Answer

The impulse on body B by body A is 120 N·s.