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The average of five numbers is 27. If one number is excluded, the average becomes 25. The excluded number is ?35552545

Question

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Solution

1. Break Down the Problem

To find the excluded number, we need to calculate the total of the five numbers and then compare it to the total when one number is excluded.

2. Relevant Concepts

  • Average Formula: The average of a set of numbers is given by the formula: Average=Sum of all numbersCount of numbers \text{Average} = \frac{\text{Sum of all numbers}}{\text{Count of numbers}}

3. Analysis and Detail

  1. Let the five numbers be represented as x1,x2,x3,x4,x5 x_1, x_2, x_3, x_4, x_5 .

  2. The average of these five numbers is 27: x1+x2+x3+x4+x55=27 \frac{x_1 + x_2 + x_3 + x_4 + x_5}{5} = 27 Hence, the sum of the five numbers is: x1+x2+x3+x4+x5=27×5=135 x_1 + x_2 + x_3 + x_4 + x_5 = 27 \times 5 = 135

  3. When one number is excluded (let's denote the excluded number as xe x_e ), the average of the remaining four numbers becomes 25: x1+x2+x3+x44=25 \frac{x_1 + x_2 + x_3 + x_4}{4} = 25 Therefore, the sum of the remaining four numbers is: x1+x2+x3+x4=25×4=100 x_1 + x_2 + x_3 + x_4 = 25 \times 4 = 100

  4. Using the equations derived: x1+x2+x3+x4+xe=135 x_1 + x_2 + x_3 + x_4 + x_e = 135 and x1+x2+x3+x4=100 x_1 + x_2 + x_3 + x_4 = 100 We can substitute the second equation into the first: 100+xe=135 100 + x_e = 135

4. Verify and Summarize

Now, we solve for xe x_e : xe=135100=35 x_e = 135 - 100 = 35

Final Answer

The excluded number is 35 \boxed{35} .

This problem has been solved

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