In a certain code language, if BUG = 90 and ALMS = 180, then CADET = ?153165175148

To solve this problem, we will analyze the given codes and establish a pattern or rule that leads to the final code.

1. Break Down the Problem

• We need to find the value of "CADET" based on the given values of "BUG" and "ALMS."
• The codes for "BUG" and "ALMS" seem to be derived from their constituent letters and their positions in the alphabet.

2. Relevant Concepts

• Each letter can be converted to its corresponding position in the English alphabet:
  • A = 1, B = 2, C = 3, ..., Z = 26.
• We need to find a consistent way to convert these letter positions into the numerical values provided.

3. Analysis and Detail

• For "BUG":

  • B = 2, U = 21, G = 7
  • Sum = 2 + 21 + 7 = 30
  • 30 multiplied by some factor to get 90. Here, 30 × 3 = 90.

• For "ALMS":

  • A = 1, L = 12, M = 13, S = 19
  • Sum = 1 + 12 + 13 + 19 = 45
  • 45 multiplied by 4 gives 180. Here, 45 × 4 = 180.

From this, we can discern:

• The formula for computation for the code might involve summing the positions of the letters and then multiplying by a factor which corresponds to the number of letters (3 for "BUG," 4 for "ALMS").

4. Verify and Summarize

Now, let's apply this understanding to the word "CADET":

• C = 3, A = 1, D = 4, E = 5, T = 20
• Sum = 3 + 1 + 4 + 5 + 20 = 33
• There are 5 letters in "CADET," so we'll multiply by 5:
• Final Calculation: 33 × 5 = 165.

Final Answer

The code for "CADET" is 165.