NFA doesn’t require to show transitions for all input symbols in alphabet set over a statea.trueb.false
Question
NFA doesn’t require to show transitions for all input symbols in alphabet set over a state
a. true
b. false
Solution
Understanding NFA Transitions
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Definition of NFA: A Non-deterministic Finite Automaton (NFA) is a theoretical model of computation equivalent to a deterministic finite automaton (DFA). It consists of states, transitions, and acceptance conditions.
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Transition Function: In an NFA, the transition function allows for multiple transitions for a single state given an input symbol. This is in contrast to a DFA, where each state has exactly one transition for each symbol in the alphabet.
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Input Symbols and Transitions: Unlike DFAs, NFAs do not require a transition for every input symbol for every state. This means that it is possible for an NFA to have states where certain input symbols do not lead to any transition. Indeed, it can also allow for "epsilon" (ε) transitions, which change states without consuming an input symbol.
Analysis of the Statement
- The statement mentions that "NFA doesn’t require to show transitions for all input symbols in alphabet set over a state."
- Given the properties of NFAs, this statement is true, as it correctly reflects that NFAs can have certain states without transitions for every input symbol.
Final Answer
a. True
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