Balance the following chemical equation. (Remember to enter a "1" where you have a blank in front of a molecule/compound) AlBr3 + Cl2 --> AlCl3 + Br2
Question
Balance the following chemical equation. (Remember to enter a "1" where you have a blank in front of a molecule/compound)
Equation:
AlBr3 + Cl2 --> AlCl3 + Br2
Solution
To balance the chemical equation AlBr3 + Cl2 --> AlCl3 + Br2, follow these steps:
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Write down the unbalanced equation: AlBr3 + Cl2 --> AlCl3 + Br2
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Balance the equation by adjusting the coefficients (the numbers in front of atoms or compounds) to ensure that the number of atoms for each element is the same on both sides of the equation.
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Start by balancing the Aluminium (Al) atoms. In this case, they are already balanced with one Al atom on both sides.
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Next, balance the Bromine (Br) atoms. There are 3 Br atoms on the left side and 2 on the right side. To balance them, you can put a coefficient of 2 in front of AlBr3 and a coefficient of 3 in front of Br2. The equation now looks like this: 2AlBr3 + Cl2 --> AlCl3 + 3Br2
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Now, balance the Chlorine (Cl) atoms. There are 2 Cl atoms on the left side and 3 on the right side. To balance them, you can put a coefficient of 3 in front of Cl2 and a coefficient of 2 in front of AlCl3. The equation now looks like this: 2AlBr3 + 3Cl2 --> 2AlCl3 + 3Br2
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Finally, check to make sure that the equation is balanced. There are 2 Al, 6 Br, and 6 Cl atoms on both sides of the equation, so the equation is balanced.
So, the balanced equation is: 2AlBr3 + 3Cl2 --> 2AlCl3 + 3Br2
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