A dealer sells his goods at C.P.If by using false weights he gains 4 823%, then find the weight he uses for 1Kg.900 gm958.34 gm836.24 gmNone of these
Question
A dealer sells his goods at C.P. If by using false weights he gains 4 823%, then find the weight he uses for 1 Kg.
- 900 gm
- 958.34 gm
- 836.24 gm
- None of these
Solution
The dealer is gaining 4 823% by using false weights. This means that for every 1 Kg (1000 gm), he is actually giving less than that.
Let's denote the actual weight he gives as 'W'.
We know that the gain percent is given by the formula:
Gain% = [(True Value - False Value) / False Value] * 100
In this case, the gain is 4.823% (or 0.04823 in decimal form), the True Value is 1000 gm (1 Kg), and the False Value is 'W'.
Substituting these values into the formula, we get:
0.04823 = [(1000 - W) / W]
Solving this equation for 'W' gives us:
W = 1000 / (1 + 0.04823) = 953.68 gm
So, the dealer is using a weight of approximately 953.68 gm for 1 Kg.
The closest option to this value is 958.34 gm. So, the answer is 958.34 gm.
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