A group consists of 4 girls and 7 boys. In how many ways can a group of 5 members be selected if the team has no girls?

The question is asking for the number of ways to select a group of 5 members from a total of 7 boys (since we're not considering the girls).

This is a combination problem, because the order in which we select the boys does not matter.

The formula for combinations is C(n, r) = n! / [r!(n-r)!], where n is the total number of options, r is the number of options chosen, and "!" denotes factorial.

In this case, n = 7 (the total number of boys) and r = 5 (the number of boys we want to select).

So, we plug these values into the formula:

C(7, 5) = 7! / [5!(7-5)!] = 7! / [5! * 2!]

= (7654321) / [(54321) * (2*1)]

= (76) / (21)

= 21

So, there are 21 ways to select a group of 5 members from 7 boys.