StudyGPT Just Leveled Up – Say Hello to Knowee! 🚀
Knowee
Questions
Features
Study Tools

Look at the equation below. How much force would it take for a 1000 kg car that is travelling at 30 m/s to come to a stop within 3 seconds?

Question

Look at the equation below. How much force would it take for a 1000 kg car that is travelling at 30 m/s to come to a stop within 3 seconds?

🧐 Not the exact question you are looking for?Go ask a question

Solution

The problem can be solved using Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration (F = ma).

First, we need to find the acceleration of the car. Acceleration is the rate of change of velocity per unit of time. In this case, the car is decelerating from 30 m/s to 0 m/s in 3 seconds. So, the acceleration (a) can be calculated as:

a = (final velocity - initial velocity) / time a = (0 m/s - 30 m/s) / 3 s a = -10 m/s²

The negative sign indicates that this is a deceleration.

Next, we can find the force (F) using the formula F = ma:

F = 1000 kg * -10 m/s² F = -10000 N

The negative sign indicates that the force is acting in the opposite direction to the motion of the car. So, it would take a force of 10000 N to bring the car to a stop within 3 seconds.

This problem has been solved

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.