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If yx02 4082= −; ; ;E E E, the value of x and y respectively are :(a) 1, -2 (b) -2, 1(c) 1, 2

Question

If yx02 4082= −; ; ;E E E, the value of x and y respectively are :

(a) 1, -2

(b) -2, 1

(c) 1, 2

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Solution

Break Down the Problem

  1. We need to solve for the values of xx and yy given the equation yx24082=0 yx^2 - 4082 = 0 , where E E represents some equality condition.

Relevant Concepts

  1. Rearranging the equation, we have: yx2=4082 yx^2 = 4082 This indicates that yy and xx are related through the product yx2yx^2.

Analysis and Detail

  1. We can analyze the given options by substituting the values of xx and yy from options (a), (b), and (c) into the rearranged equation:
    • For option (a): (x,y)=(1,2) (x, y) = (1, -2) 2(1)2=2(not equal to 4082) -2(1)^2 = -2 \quad \text{(not equal to 4082)}
    • For option (b): (x,y)=(2,1) (x, y) = (-2, 1) 1(2)2=4(not equal to 4082) 1(-2)^2 = 4 \quad \text{(not equal to 4082)}
    • For option (c): (x,y)=(1,2) (x, y) = (1, 2) 2(1)2=2(not equal to 4082) 2(1)^2 = 2 \quad \text{(not equal to 4082)}

Verify and Summarize

  1. After substituting all options into the equation, none resulted in the equality being satisfied (yx2=4082yx^2 = 4082). Since yy must be negative for any realistic values in this set-up to fit with negative results. Thus, without additional information, there is likely to be a typographical or contextual error in the problem statement.

Final Answer

None of the provided options satisfy the equation yx2=4082yx^2 = 4082. Additional context or correction may be needed for a valid solution.

This problem has been solved

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