The sum of four consecutive integers is 1290.The greatest of them is?Options220760324NONE
Question
The sum of four consecutive integers is 1290. The greatest of them is?
Options:
- 220
- 760
- 324
- NONE
Solution
Let's denote the four consecutive integers as x, x+1, x+2, and x+3.
Given that their sum is 1290, we can write the equation as:
x + (x+1) + (x+2) + (x+3) = 1290
Solving this equation:
4x + 6 = 1290
Subtract 6 from both sides:
4x = 1284
Divide by 4:
x = 321
So, the four consecutive numbers are 321, 322, 323, and 324.
Therefore, the greatest of them is 324. So, the correct option is 324.
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