A wave whose frequency is 500 Hz -1 has a speed of 400 m s-1' What is the minimum distance between twopoints where the phase difference of this wave is /4@
Question
Solution 1
The phase difference of π/4 corresponds to a quarter of the wavelength.
The formula for the speed of a wave is v = fλ, where v is the speed, f is the frequency, and λ is the wavelength.
We can rearrange this formula to solve for the wavelength: λ = v/f.
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