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Find the inverse of the matrix A = [2 5; 1 3]. a. [3 -5; -1 2] b. [3 -1; -5 2] c. [2 -5; 1 3] d. [3 1; -5 2]

Question

Find the inverse of the matrix A = [2 5; 1 3].

a. [3 -5; -1 2]

b. [3 -1; -5 2]

c. [2 -5; 1 3]

d. [3 1; -5 2]

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Solution

The inverse of a 2x2 matrix [a b; c d] is given by 1/(ad-bc) * [d -b; -c a].

So, for the matrix A = [2 5; 1 3], the determinant (ad-bc) is (23 - 51) = 1.

Therefore, the inverse of A is 1/1 * [3 -5; -1 2], which simplifies to [3 -5; -1 2].

So, the correct answer is:

a. [3 -5; -1 2]

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