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What is the process of defining more than one method in a class differentiated by method signature?

Question

What is the process of defining more than one method in a class differentiated by method signature?

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Solution

The process of defining more than one method in a class differentiated by method signature is known as method overloading. Here are the steps to do it:

  1. Define a class: The first step is to define a class where you will overload methods.
public class MyClass {
    // class body
}
  1. Define methods with the same name but different parameters: Inside the class, you can define multiple methods with the same name but different parameters. This is the key aspect of method overloading. The parameters can differ in type, number, or order.
public class MyClass {
    void myMethod(int a) {
        // method body
    }

    void myMethod(double b) {
        // method body
    }

    void myMethod(int a, double b) {
        // method body
    }

    void myMethod(double b, int a) {
        // method body
    }
}

In the above example, all methods have the same name 'myMethod' but different parameters. This is method overloading.

  1. Call the methods: Now, you can create an object of the class and call these methods. The appropriate method will be called based on the parameters you pass.
public class Main {
    public static void main(String[] args) {
        MyClass obj = new MyClass();
        obj.myMethod(10); // calls the method with int parameter
        obj.myMethod(10.5); // calls the method with double parameter
        obj.myMethod(10, 10.5); // calls the method with int and double parameters
        obj.myMethod(10.5, 10); // calls the method with double and int parameters
    }
}

In this way, you can define more than one method in a class differentiated by method signature, which is known as method overloading.

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