What will be the output of the following pseudocode?Integer p, q, rset p=1, q=2, r=0if (p < q )p= p << 1if ( p > q ) r= r << 1end ifprintf p + q + r

The pseudocode provided is a simple program that uses bitwise shift operations and conditional statements. Here's a step-by-step breakdown of what it does:

1. Three integer variables p, q, r are declared.
2. The variables p, q, r are initialized with the values 1, 2, 0 respectively.
3. A conditional statement checks if p is less than q. Since 1 is less than 2, the condition is true.
4. Inside the first condition, a left shift operation is performed on p. The left shift operation "p << 1" means "shift the bits of p one place to the left". In binary, 1 is represented as 01. When we shift these bits one place to the left, we get 10, which is 2 in decimal. So now, p becomes 2.
5. The next conditional statement checks if p is greater than q. But since p and q are both 2, this condition is false. So, the operation inside this condition "r << 1" is not performed and r remains 0.
6. Finally, the values of p, q, and r are added together and printed. So, the output will be 2 (value of p) + 2 (value of q) + 0 (value of r) = 4.