A 0.5 m long solenoid has 500 turns and has a flux density of 2.512 X 10-3 T atits center. Find the current in solenoid. Given μ0 = 4π X 10 -7 H/m ,Π =3.14
Question
Solution 1
The magnetic field B inside a solenoid is given by the formula B = μ0 * n * I, where:
- B is the magnetic field,
- μ0 is the permeability of free space,
- n is the number of turns per unit length,
- I is the current.
We can rearrange this formula to solve for I: I = B / (μ0 * n).
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