A micrometer screw has a pitch of 0.5 mm. the circular scale is divided into 50 parts. The least ofmicrometer is

1. Break Down the Problem

To find the least count of the micrometer screw, we need to understand the relationship between the pitch of the screw and the divisions on the circular scale.

2. Relevant Concepts

• Pitch of Micrometer Screw: This is the distance moved by the screw in one complete rotation.
• Circular Scale Divisions: This indicates how many divisions there are on the circular scale.
• Least Count: The least count (LC) of a micrometer screw is given by the formula:

$\text{Least Count (LC)} = \frac{\text{Pitch}}{\text{Number of divisions on the circular scale}}$

3. Analysis and Detail

Given:

• Pitch = 0.5 mm
• Number of divisions on the circular scale = 50

Substituting into the formula:

$\text{LC} = \frac{0.5 \text{ mm}}{50}$

Calculating:

1. Divide 0.5 by 50: $\text{LC} = 0.5 \div 50 = 0.01 \text{ mm}$

4. Verify and Summarize

The calculations are correct; we have divided the pitch by the number of divisions accurately.

Final Answer

The least count of the micrometer screw is $0.01 \, \text{mm}$.