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What is the product of square root of, 6, end square root 6​ and 2, square root of, 15, end square root2 15​ in simplest radical form?

Question

What is the product of 6 \sqrt{6} and 215 2 \sqrt{15} in simplest radical form?

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Solution

To find the product of √6 and 2√15 in simplest radical form, follow these steps:

  1. Multiply the numbers outside the square roots together. In this case, it's just 2.
  2. Multiply the numbers inside the square roots together. In this case, it's 6 * 15 = 90.
  3. Simplify the square root of the product. The square root of 90 can be simplified to 3√10 because 90 = 9 * 10 and the square root of 9 is 3.
  4. Multiply the results from steps 1 and 3 together. In this case, it's 2 * 3√10 = 6√10.

So, the product of √6 and 2√15 in simplest radical form is 6√10.

This problem has been solved

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