What is the product of square root of, 6, end square root 6 and 2, square root of, 15, end square root2 15 in simplest radical form?
Question
What is the product of and in simplest radical form?
Solution
To find the product of √6 and 2√15 in simplest radical form, follow these steps:
- Multiply the numbers outside the square roots together. In this case, it's just 2.
- Multiply the numbers inside the square roots together. In this case, it's 6 * 15 = 90.
- Simplify the square root of the product. The square root of 90 can be simplified to 3√10 because 90 = 9 * 10 and the square root of 9 is 3.
- Multiply the results from steps 1 and 3 together. In this case, it's 2 * 3√10 = 6√10.
So, the product of √6 and 2√15 in simplest radical form is 6√10.
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