If 80.0% of an element has an atomic mass of 42.0 u and 20.0% has an atomic mass of 43.0 u, what is the average atomic mass of the mixture?
Question
If 80.0% of an element has an atomic mass of 42.0 u and 20.0% has an atomic mass of 43.0 u, what is the average atomic mass of the mixture?
Solution
To find the average atomic mass of the mixture, we can use the weighted average formula.
Step 1: Convert the percentages to decimal form. 80.0% becomes 0.80 and 20.0% becomes 0.20.
Step 2: Multiply each atomic mass by its corresponding percentage. For the atomic mass of 42.0 u, multiply it by 0.80. 42.0 u * 0.80 = 33.6 u.
For the atomic mass of 43.0 u, multiply it by 0.20. 43.0 u * 0.20 = 8.6 u.
Step 3: Add the weighted atomic masses together. 33.6 u + 8.6 u = 42.2 u.
Therefore, the average atomic mass of the mixture is 42.2 u.
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