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If 80.0% of an element has an atomic mass of 42.0 u and 20.0% has an atomic mass of 43.0 u, what is the average atomic mass of the mixture?

Question

If 80.0% of an element has an atomic mass of 42.0 u and 20.0% has an atomic mass of 43.0 u, what is the average atomic mass of the mixture?

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Solution

To find the average atomic mass of the mixture, we can use the weighted average formula.

Step 1: Convert the percentages to decimal form. 80.0% becomes 0.80 and 20.0% becomes 0.20.

Step 2: Multiply each atomic mass by its corresponding percentage. For the atomic mass of 42.0 u, multiply it by 0.80. 42.0 u * 0.80 = 33.6 u.

For the atomic mass of 43.0 u, multiply it by 0.20. 43.0 u * 0.20 = 8.6 u.

Step 3: Add the weighted atomic masses together. 33.6 u + 8.6 u = 42.2 u.

Therefore, the average atomic mass of the mixture is 42.2 u.

This problem has been solved

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