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A solution of 300 g contain MgCl2 worth 25 g. Find the Mass Percent of Magnesium Chloride

Question

A solution of 300 g contain MgCl2 worth 25 g. Find the Mass Percent of Magnesium Chloride

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Solution

1. Break Down the Problem

To find the mass percent of Magnesium Chloride (MgCl₂) in the solution, we need to determine the ratio of the mass of MgCl₂ to the total mass of the solution and then convert that ratio into a percentage.

2. Relevant Concepts

The formula for mass percent is given by: Mass Percent=(mass of solutetotal mass of solution)×100 \text{Mass Percent} = \left( \frac{\text{mass of solute}}{\text{total mass of solution}} \right) \times 100 Where:

  • Mass of solute = mass of MgCl₂ = 25 g
  • Total mass of solution = 300 g

3. Analysis and Detail

Using the formula:

  • Mass of solute = 25 g
  • Total mass of solution = 300 g

Plugging these values into the formula: Mass Percent=(25g300g)×100 \text{Mass Percent} = \left( \frac{25 \, \text{g}}{300 \, \text{g}} \right) \times 100

Calculating the ratio: 25300=0.0833 \frac{25}{300} = 0.0833 Now converting it to a percentage: 0.0833×100=8.33% 0.0833 \times 100 = 8.33\%

4. Verify and Summarize

Our calculations show that the mass percent of Magnesium Chloride in the solution is approximately 8.33%.

Final Answer

The mass percent of Magnesium Chloride (MgCl₂) in the solution is 8.33%.

This problem has been solved

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