What are the dimensions of the rectangle if the perimeter is 16 units and the side length is three times the breadth?

Let's denote the breadth of the rectangle as x. According to the problem, the length of the rectangle is three times the breadth, so we can denote it as 3x.

The formula for the perimeter of a rectangle is 2*(length + breadth). In this case, the perimeter is given as 16 units.

So, we can set up the equation as follows:

2*(3x + x) = 16 2*(4x) = 16 8x = 16 x = 16 / 8 x = 2 units

So, the breadth of the rectangle is 2 units.

The length of the rectangle is three times the breadth, so the length is 3*2 = 6 units.

So, the dimensions of the rectangle are 2 units by 6 units.