n Ludo, Prashant needs to repeatedly throw a unbiased die till he gets a 6. What is the probability than he needs fewer than 4 throws?

To find the probability that Prashant needs fewer than 4 throws to get a 6 in Ludo, we can consider the possible outcomes.

In the first throw, there are 6 possible outcomes, with only one of them being a 6. Therefore, the probability of getting a 6 in the first throw is 1/6.

If Prashant doesn't get a 6 in the first throw, he will need to throw the die again. In the second throw, there are still 6 possible outcomes, but now there are two favorable outcomes (getting a 6 in the second throw). So, the probability of getting a 6 in the second throw is 2/6, which simplifies to 1/3.

Similarly, if Prashant doesn't get a 6 in the second throw, he will need to throw the die again. In the third throw, there are still 6 possible outcomes, but now there are three favorable outcomes (getting a 6 in the third throw). So, the probability of getting a 6 in the third throw is 3/6, which simplifies to 1/2.

Since we are interested in the probability of needing fewer than 4 throws, we need to consider the probabilities of getting a 6 in the first, second, or third throw. We can add these probabilities together:

1/6 + 1/3 + 1/2 = 1/6 + 2/6 + 3/6 = 6/6 = 1

Therefore, the probability that Prashant needs fewer than 4 throws to get a 6 in Ludo is 1, or 100%.