A Body of mass 2kg is placed on smooth horizontal plane pulled by force 2N then the velocity of body after 3s is

To find the velocity of the body after 3 seconds, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given: Mass of the body (m) = 2 kg Force acting on the body (F) = 2 N Time (t) = 3 s

First, we need to calculate the acceleration of the body using Newton's second law:

F = m * a 2 N = 2 kg * a

Solving for acceleration (a): a = 2 N / 2 kg a = 1 m/s^2

Now, we can use the equation of motion to find the velocity of the body after 3 seconds:

v = u + a * t

Since the body is initially at rest (u = 0 m/s), the equation becomes:

v = 0 m/s + 1 m/s^2 * 3 s v = 3 m/s

Therefore, the velocity of the body after 3 seconds is 3 m/s.