The area of a trapezium is 105cm2 and its height is 7cm . If one of the parallel sides is longer than the other by 6cm , the smaller side of trapezium is
Question
The area of a trapezium is 105cm² and its height is 7cm. If one of the parallel sides is longer than the other by 6cm, the smaller side of trapezium is
Solution
The area of a trapezium is given by the formula:
Area = 1/2 * (sum of the lengths of the parallel sides) * height
We know that the area is 105 cm^2 and the height is 7 cm. We also know that one side is 6 cm longer than the other. Let's denote the shorter side as 'a' and the longer side as 'a + 6'.
Substituting these values into the formula, we get:
105 = 1/2 * (a + (a + 6)) * 7
Solving this equation will give us the length of the shorter side.
Step 1: Simplify the equation:
105 = 1/2 * (2a + 6) * 7
Step 2: Divide both sides by 7:
15 = 1/2 * (2a + 6)
Step 3: Multiply both sides by 2:
30 = 2a + 6
Step 4: Subtract 6 from both sides:
24 = 2a
Step 5: Divide both sides by 2 to solve for 'a':
a = 12
So, the shorter side of the trapezium is 12 cm.
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