A number is increased by 20% and then it is decreased by 20%. Find the net increase or decrease per cent.
Question
A number is increased by 20% and then it is decreased by 20%. Find the net increase or decrease per cent.
Solution
Sure, let's solve the problem step by step.
Step 1: Let's assume the number is x.
Step 2: The number is increased by 20%. This means we need to find 20% of x and add it to x.
20% of x = (20/100) * x = 0.2x
So, the new number after the increase is x + 0.2x = 1.2x.
Step 3: The number is then decreased by 20%. This means we need to find 20% of 1.2x and subtract it from 1.2x.
20% of 1.2x = (20/100) * 1.2x = 0.24x
So, the final number after the decrease is 1.2x - 0.24x = 0.96x.
Step 4: To find the net increase or decrease percentage, we need to compare the final number (0.96x) with the original number (x).
Net increase or decrease percentage = ((final number - original number) / original number) * 100
= ((0.96x - x) / x) * 100
= (-0.04x / x) * 100
= -4%
Therefore, the net increase or decrease percentage is -4%.
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