To solve this problem, we need to understand that the roll of a die is an independent event, meaning that the outcome of the first roll does not affect the outcome of the second roll.

Step 1: Determine the probability of rolling a 1 on a die. A die has 6 faces, so the probability of rolling a 1 (or any specific number) is 1 out of 6, or 1/6.

Step 2: Determine the probability of rolling an even number on a die. The even numbers on a die are 2, 4, and 6. So there are 3 favorable outcomes out of 6 possible outcomes, which gives a probability of 3/6 or 1/2.

Step 3: Since these are independent events, we multiply the probabilities together to get the overall probability. So, the probability of rolling a 1 first, followed by rolling an even number is (1/6) * (1/2) = 1/12.

Question

To solve this problem, we need to understand that the roll of a die is an independent event, meaning that the outcome of the first roll does not affect the outcome of the second roll.

Step 1: Determine the probability of rolling a 1 on a die. A die has 6 faces, so the probability of rolling a 1 (or any specific number) is 1 out of 6, or 1/6.

Step 2: Determine the probability of rolling an even number on a die. The even numbers on a die are 2, 4, and 6. So there are 3 favorable outcomes out of 6 possible outcomes, which gives a probability of 3/6 or 1/2.

Step 3: Since these are independent events, we multiply the probabilities together to get the overall probability. So, the probability of rolling a 1 first, followed by rolling an even number is (1/6) * (1/2) = 1/12.

Knowee AI · Accepted Answer

To solve this problem, we need to understand that the roll of a die is an independent event, meaning that the outcome of the first roll does not affect the outcome of the second roll.

Step 1: Determine the probability of rolling a 1 on a die. A die has 6 faces, so the probability of rolling a 1 (or any specific number) is 1 out of 6, or 1/6.

Step 2: Determine the probability of rolling an even number on a die. The even numbers on a die are 2, 4, and 6. So there are 3 favorable outcomes out of 6 possible outcomes, which gives a probability of 3/6 or 1/2.

Step 3: Since these are independent events, we multiply the probabilities together to get the overall probability. So, the probability of rolling a 1 first, followed by rolling an even number is (1/6) * (1/2) = 1/12.

A die is rolled twice. What is the probability rolling a 1 first, followed by rolling an even number? Leave your answer as a reduced fraction.

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