If a reaction has Keq = 1, which best describes the change in free energy, ΔG, for that reaction?

Question

If a reaction has Keq = 1, which best describes the change in free energy, ΔG, for that reaction?
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

The equilibrium constant (Keq) of a reaction is related to the change in free energy (ΔG) through the equation ΔG = -RTlnKeq, where R is the gas constant and T is the temperature in Kelvin.

If Keq = 1, then lnKeq = ln(1) = 0. Therefore, ΔG = -RT*0 = 0.

So, if a reaction has Keq = 1, the change in Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

If a reaction has Keq = 1, which best describes the change in free energy, ΔG, for that reaction?

If the change in free energy (ΔG) is , the reaction is spontaneous under the conditions specified. If ΔG is , the reaction is not spontaneous.

For the reaction H2(g) + I2(g) ⇔ 2HI (g), the standard free energy is ΔG⊖ > 0. The equilibrium constant (K ) would be

The standard free energy change (ΔG°) for 50% dissociation of N2O4 into NO2 at 27 °C and 1 atm pressure is −x J mol−1 . The value of x

If ΔG>O for a chemical reaction, then the reaction is _____.Group of answer choicesendergonicexergonic

1/3