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A 16 x 5 ROM storesa.5 words of 16 bits eachb.4 words of 16 bits eachc.16 words of 4 bits each

Question

A 16 x 5 ROM stores:

a. 5 words of 16 bits each
b. 4 words of 16 bits each
c. 16 words of 4 bits each

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Solution

The statement seems to be incomplete. However, I can provide an explanation based on the information given.

A 16 x 5 ROM means that the ROM has 16 address lines and 5 data lines.

This means that the ROM can store 2^16 (or 65,536) different addresses. Since each address can store 5 bits of data, the total storage capacity of the ROM is 65,536 * 5 bits.

Now, let's look at the options:

a. 5 words of 16 bits each: This would require a total of 5 * 16 = 80 bits. The ROM has more storage than this.

b. 4 words of 16 bits each: This would require a total of 4 * 16 = 64 bits. The ROM has more storage than this.

c. 16 words of 4 bits each: This would require a total of 16 * 4 = 64 bits. The ROM has more storage than this.

So, based on the information given, the ROM could store any of these options, but it has the capacity to store much more.

This problem has been solved

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