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Find the empirical formula of a compound that is 53.7% iron and 46.3% sulfur.What is the empirical mass of the said compound in g/mol?Use:Fe = 56 amuS = 32 amu

Question

Find the empirical formula of a compound that is 53.7% iron and 46.3% sulfur.What is the empirical mass of the said compound in g/mol?Use:Fe = 56 amuS = 32 amu
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Solution 1

Step 1: Assume you have 100g of the compound. This means you have 53.7g of iron (Fe) and 46.3g of sulfur (S).

Step 2: Convert the mass of each element to moles.

For iron: 53.7g Fe * (1 mol Fe / 56g Fe) = 0.96 mol Fe

For sulfur: 46.3g S * (1 mol S / 32g S) = 1.45 mol S

Step 3: Write the ratio Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
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