A Zener diode has a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. What is the maximum current that the diode can withstand ?
Question
Solution 1
The maximum current that the diode can withstand can be calculated using Ohm's Law, which states that the current (I) is equal to the power (P) divided by the voltage (V).
Given:
- Breakdown voltage (V) = 9.1 V
- Maximum power dissipation (P) = 364 mW = 0.364 W (since 1W = 1000mW)
We can substitu Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI
Similar Questions
he zener diode is designed to operate in *(14 of 25)4 answers to the question.cutoffforward bias saturation zener breakdown
n Zener breakdown the depletion region of pn junction diode is____________________a)none of the mentionedb)Narrowc)collapesd)wider
If a silicon diode is operating in forward bias in a circuit with 12 V supply and 240 Ω resistor, then what will be the voltage drop across the diode?
When the diode is reverse biased with a voltage of 9V and Vbias=0.54V. So, the total potential will be A- 9.54 V B- 9 V C- 8.46 V D- 0.06 V
An a.c. voltage of peak value 20 V is connected in series with a silicon diode and load resistance of 500 Ω. If the forward resistance of diode is 10 Ω, find :
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.