A Zener diode has a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. What is the maximum current that the diode can withstand ?
Question
A Zener diode has a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. What is the maximum current that the diode can withstand ?
Solution
The maximum current that the diode can withstand can be calculated using Ohm's Law, which states that the current (I) is equal to the power (P) divided by the voltage (V).
Given:
- Breakdown voltage (V) = 9.1 V
- Maximum power dissipation (P) = 364 mW = 0.364 W (since 1W = 1000mW)
We can substitute these values into the formula:
I = P / V I = 0.364 W / 9.1 V I = 0.04 A or 40 mA
Therefore, the maximum current that the diode can withstand is 40 mA.
Similar Questions
he zener diode is designed to operate in *(14 of 25)4 answers to the question.cutoffforward bias saturation zener breakdown
n Zener breakdown the depletion region of pn junction diode is____________________a)none of the mentionedb)Narrowc)collapesd)wider
An electric kettle is rated at 230V, 1000W. What is the safe value of current that can pass through its element?
What will be the power dissipation across a silicon diode carrying a current of 50mA?Choose the best optionClear Response25mW5OmW35mW100mW
Zener diodes are sometimes used as *(16 of 25)4 answers to the question.voltage references current limiters variable resistorspower distributors
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.