A Zener diode has a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. What is the maximum current that the diode can withstand ?
Question
Solution
The maximum current that the diode can withstand can be calculated using Ohm's Law, which states that the current (I) is equal to the power (P) divided by the voltage (V).
Given:
- Breakdown voltage (V) = 9.1 V
- Maximum power dissipation (P) = 364 mW = 0.364 W (since 1W = 1000mW)
We can substitute these values into the formula:
I = P / V I = 0.364 W / 9.1 V I = 0.04 A or 40 mA
Therefore, the maximum current that the diode can withstand is 40 mA.
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