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An employee saving for retirement invests $7,500 for 34 months at . How much interest will be earned on this investment? Round to the nearest cent.

Question

An employee saving for retirement invests $7,500 for 34 months at . How much interest will be earned on this investment? Round to the nearest cent.

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Solution

To determine the interest earned on the investment, we need to know the interest rate and whether it is simple or compound interest. Since the interest rate is not provided, I'll assume it is simple interest for this calculation.

The formula for simple interest is:

Interest=P×r×t \text{Interest} = P \times r \times t

where:

  • P P is the principal amount ($7,500),
  • r r is the annual interest rate (expressed as a decimal),
  • t t is the time the money is invested for (in years).

First, convert the time from months to years:

t=34 months12 months/year=2.8333 years t = \frac{34 \text{ months}}{12 \text{ months/year}} = 2.8333 \text{ years}

Next, we need the interest rate r r . Since it is not provided, let's assume an interest rate of 5% (0.05 as a decimal) for the sake of this example.

Now, plug the values into the formula:

Interest=7500×0.05×2.8333 \text{Interest} = 7500 \times 0.05 \times 2.8333

Interest=7500×0.05×2.8333=7500×0.141665=1062.49 \text{Interest} = 7500 \times 0.05 \times 2.8333 = 7500 \times 0.141665 = 1062.49

Therefore, the interest earned on the investment is approximately $1,062.49.

This problem has been solved

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