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The figure below is made up of a rectangle and two identical squares. AB is twice the length of BQ. What is the length of PQ if AB is 14 cm long.

Question

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Solution

1. Break Down the Problem

The problem involves a rectangle and two identical squares. We need to determine the length of PQ PQ . Given that AB AB is twice the length of BQ BQ and AB=14 AB = 14 cm, we can express BQ BQ in terms of AB AB .

2. Relevant Concepts

In this case:

  • Let BQ=x BQ = x .
  • Therefore, since AB AB is twice BQ BQ , we have: AB=2BQ=2x AB = 2 \cdot BQ = 2x
  • Given AB=14 AB = 14 cm, we can set up the equation: 2x=14 2x = 14

3. Analysis and Detail

Now we will solve for x x :

  1. Divide both sides of the equation by 2: x=142=7 cm x = \frac{14}{2} = 7 \text{ cm}
  2. So, BQ=7 BQ = 7 cm.

4. Verify and Summarize

Now that we have BQ=7 BQ = 7 cm, PQ PQ is equal to BQ BQ since both squares are identical and the side lengths of the squares are equal to BQ BQ .

Final Answer

Thus, the length of PQ PQ is 7 7 cm.

This problem has been solved

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