If CuSO will dissociate into ions; then formed ions will be :(1) Cu , SO(2) Cu , SO(3) Cu , SO(4) Cu , SO24+ 4–++ 4– –– – 4+ +– 4+

To determine the ions formed when CuSO (Copper(I) sulfate) dissociates in solution, we need to look at its chemical composition.

Step 1: Identifying the Compound

Copper(I) sulfate is represented by the formula Cu2SO4. It consists of copper ions and sulfate ions.

Step 2: Dissociation of the Compound

When Cu2SO4 dissolves in water, it dissociates into its constituent ions according to the following reaction:

$\text{Cu}_2\text{SO}_4 \rightarrow 2\text{Cu}^+ + \text{SO}_4^{2-}$

Step 3: Identifying the Ions

From the dissociation, we can identify the ions formed:

1. Two Cu$^{+}$ ions (copper(I) ions)
2. One SO$_4^{2-}$ ion (sulfate ion)

Step 4: Conclusion

Thus, when Cu2SO4 (Copper(I) sulfate) dissociates in solution, it forms:

• 2 Cu$^+$ ions
• 1 SO$_4^{2-}$ ion

Final Answer

The formed ions from the dissociation of Cu2SO4 are: 2 Cu$^+$ and 1 SO$_4^{2-}$.