What will be the value of n-factor (nf) or valence factor of P in Ca3P2 and H3PO4 respectively for the following change?Ca3P2⟶H3PO4
Question
What will be the value of n-factor (nf) or valence factor of P in Ca3P2 and H3PO4 respectively for the following change?
Ca3P2 ⟶ H3PO4
Solution
The n-factor or valence factor of an element in a chemical reaction is the total change in the oxidation number per formula unit of the substance.
-
In Ca3P2: The oxidation state of P (Phosphorus) is -3.
-
In H3PO4: The oxidation state of P (Phosphorus) is +5.
The change in oxidation state from Ca3P2 to H3PO4 is from -3 to +5, which is a total change of 8. However, since there are 2 P atoms in Ca3P2, the n-factor will be 8*2 = 16.
So, the n-factor of P in the given reaction is 16.
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