If two sets are such that n (A intersection B) = ½ (AUB) = 6. Then a total number of elements in these sets is?A.9B.12C.16D.18
Question
If two sets are such that
n (A intersection B) = ½ (AUB) = 6.
Then a total number of elements in these sets is?
A. 9
B. 12
C. 16
D. 18
Solution
To find the total number of elements in the sets A and B, we can use the formula for the union of two sets:
n(AUB) = n(A) + n(B) - n(A intersection B)
Given that n(A intersection B) = 6 and n(AUB) = ½ (AUB) = 6, we can substitute these values into the formula:
6 = n(A) + n(B) - 6
Rearranging the equation, we get:
n(A) + n(B) = 12
Since the number of elements in A and B is equal to the sum of the number of elements in each set, the total number of elements in these sets is 12.
Therefore, the correct answer is B. 12.
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