our aunt Petunia invests $1000 in a high interest savings account at an APR of 2.3%,compounded daily for 3 years

Sure, I can help with that. The formula for compound interest is A = P(1 + r/n)^(nt), where:

• A is the amount of money accumulated after n years, including interest.
• P is the principal amount (the initial amount of money).
• r is the annual interest rate (in decimal).
• n is the number of times that interest is compounded per year.
• t is the time the money is invested for in years.

Given that P = $1000, r = 2.3/100 = 0.023 (you have to divide by 100 to convert the percentage into a decimal), n = 365 (since the interest is compounded daily), and t = 3 years, we can substitute these values into the formula:

A = 1000(1 + 0.023/365)^(365*3)

Now, calculate the expression in the parentheses:

1 + 0.023/365 = 1.0000630137

Then, raise this result to the power of 365*3:

(1.0000630137)^(365*3) = 1.071320244

Finally, multiply this result by the principal amount:

1000 * 1.071320244 = $1071.32

So, after 3 years, Aunt Petunia will have approximately $1071.32 in her savings account.