The solubility of Pb(OH)2 in water is 6.75 ×10–6 M. Its solubility in a buffer solution of pH = 8 would be
Question
Solution 1
To determine the solubility of Pb(OH)2 in a buffer solution of pH = 8, we need to consider the equilibrium reaction of Pb(OH)2 in water:
Pb(OH)2 (s) ⇌ Pb2+ (aq) + 2OH- (aq)
The solubility of Pb(OH)2 is given as 6.75 × 10–6 M in water. This means that at equilibrium, the concentration of Pb2+ ions Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
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Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
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