What will be the output of the following Python code snippet?print('{:#}'.format(1010101010))Options101,010,101,01,010,101,0101010101010Error

To determine the output of the given Python code snippet, we need to analyze the string formatting syntax used in the print() function.

Breakdown of the Problem:

1. The code snippet is using the format() method of strings to format the number 1010101010.
2. The formatting specification '{:#}' indicates that the number should be formatted in a specific way.

Relevant Concepts:

• The # in the format specification is a flag that indicates the inclusion of the 0b prefix for binary representations, 0o for octal, and 0x for hexadecimal. However, since we are formatting an integer number directly without specifying a base (binary, octal, or hexadecimal), we don't expect the prefix here.

Analysis and Detail:

1. The number 1010101010 is treated as a decimal integer.
2. Applying the format '{:#}' on the integer will attempt to promote the formatting to hexadecimal by default due to how the # is interpreted in an integer context without a specified type.

Thus, formatting it directly results in converting the decimal number to hexadecimal, which gives us the following:

• Decimal 1010101010 equals 3CDAA9B2 in hexadecimal.

Given that there is no appropriate continuation of this specific formatting to a straightforward integer representation, and it appears not to have a valid printing outcome directly related to the other options provided.

Verify and Summarize:

The expected behavior based on the interpretation of this formatting does not yield any of the options provided (such as grouping the digits).

Final Answer:

Error