For a gaseous reaction: A + 2B <---> 2C, increasing pressure from 10 to 20 bar will increase the products formation
Question
For a gaseous reaction:
A + 2B <---> 2C
Increasing pressure from 10 to 20 bar will increase the products formation.
Solution
The effect of pressure on the equilibrium of a gaseous reaction is determined by the change in the number of moles of gas in the reaction. In the given reaction: A + 2B <---> 2C, the number of moles of gas on both sides of the reaction is the same (3 moles on both sides). Therefore, according to Le Chatelier's principle, which states that a system at equilibrium will adjust to counteract any change in conditions, an increase in pressure will not favor the formation of products or reactants. The system will remain at equilibrium. So, increasing the pressure from 10 to 20 bar will not increase the formation of the products in this case.
Similar Questions
Which of the following is a way to decrease the pressure of a gas?increase the volumeincrease the number of moleculesdecrease the volume
A gas expands from 10L to 100L against an external pressure of 2 atom. The work is
Which of the following methods will enable the volume of ideal gas to be increased four times?
Which of the following metal does not produce H2 gas after reaction with dil. acid ?A Mg B Na C K D Cu
What chemical reaction results in the formation of a solid? A. acid base reaction B. endothermic C. precipitate
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.