What is the number of moles in 432 g Ba(NO)?Group of answer choices0.237 mol1.65 mol3.66 mol0.605 mol

1. Break Down the Problem

To determine the number of moles in 432 g of Ba(NO₃)₂, we need to use the formula for calculating moles: $\text{Number of moles} = \frac{\text{Mass (g)}}{\text{Molar mass (g/mol)}}$

2. Relevant Concepts

First, we need to calculate the molar mass of Ba(NO₃)₂.

• Barium (Ba) has an atomic mass of approximately 137.33 g/mol.
• Nitrogen (N) has an atomic mass of approximately 14.01 g/mol.
• Oxygen (O) has an atomic mass of approximately 16.00 g/mol.

The formula Ba(NO₃)₂ consists of:

• 1 Ba
• 2 N
• 6 O (since there are 3 oxygens in each nitrate and there are two nitrates)

3. Analysis and Detail

Let's calculate the molar mass of Ba(NO₃)₂:

$\text{Molar mass of Ba(NO}_3\text{)}_2 = (1 \times 137.33) + (2 \times 14.01) + (6 \times 16.00)$ Calculating each component:

1. $1 \times 137.33 = 137.33$
2. $2 \times 14.01 = 28.02$
3. $6 \times 16.00 = 96.00$

Now, summing them up: $\text{Molar mass} = 137.33 + 28.02 + 96.00 = 261.35 \text{ g/mol}$

4. Verify and Summarize

Now we can calculate the number of moles in 432 g of Ba(NO₃)₂: $\text{Number of moles} = \frac{432 \text{ g}}{261.35 \text{ g/mol}} \approx 1.65 \text{ mol}$

Final Answer

The number of moles in 432 g of Ba(NO₃)₂ is approximately 1.65 mol.