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A block of aluminum occupies a volume of 15.0 mL and weighs 40.5 g. What is its density?

Question

A block of aluminum occupies a volume of 15.0 mL and weighs 40.5 g. What is its density?

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Solution

1. Break Down the Problem

To find the density of the aluminum block, we need to use the formula for density:

Density=MassVolume \text{Density} = \frac{\text{Mass}}{\text{Volume}}

Where:

  • Mass is given as 40.5g 40.5 \, \text{g}
  • Volume is given as 15.0mL 15.0 \, \text{mL}

2. Relevant Concepts

The relevant formula for density has already been stated. Density is a property that relates the mass of a substance to its volume.

3. Analysis and Detail

To calculate the density, we will substitute the values into the density formula.

Density=40.5g15.0mL \text{Density} = \frac{40.5 \, \text{g}}{15.0 \, \text{mL}}

Now, we will carry out the calculation:

Density=2.7g/mL \text{Density} = 2.7 \, \text{g/mL}

4. Verify and Summarize

The calculation has been verified. The density calculation is based on the straightforward application of the density formula using the provided mass and volume values.

Final Answer

The density of the aluminum block is 2.7g/mL 2.7 \, \text{g/mL} .

This problem has been solved

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