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A 30 g bullet leaver a rifle with a velocity of 300 m/s and the rifle recoils with a velocity of 0.60 m/s. Find the mass of the rifle.

Question

A 30 g bullet leaves a rifle with a velocity of 300 m/s and the rifle recoils with a velocity of 0.60 m/s. Find the mass of the rifle.

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Solution

To find the mass of the rifle, we can use the principle of conservation of momentum. According to this principle, the total momentum before the bullet is fired is equal to the total momentum after the bullet is fired.

The momentum of an object is given by the product of its mass and velocity. Let's denote the mass of the rifle as "m" and the mass of the bullet as "m_b". The velocity of the bullet is given as 300 m/s, and the velocity of the rifle is given as 0.60 m/s.

Before the bullet is fired, the total momentum is zero since both the rifle and the bullet are at rest. After the bullet is fired, the total momentum is the sum of the momentum of the bullet and the momentum of the rifle.

The momentum of the bullet is given by the product of its mass and velocity: m_b * 300 m/s. The momentum of the rifle is given by the product of its mass and velocity: m * 0.60 m/s.

According to the conservation of momentum, the total momentum before and after the bullet is fired should be equal. Therefore, we can write the equation:

0 = m_b * 300 m/s + m * 0.60 m/s

Since the mass of the bullet is given as 30 g (or 0.03 kg), we can substitute this value into the equation:

0 = 0.03 kg * 300 m/s + m * 0.60 m/s

Simplifying the equation, we have:

0 = 9 kg m/s + 0.60 m/s * m

To solve for the mass of the rifle, we can rearrange the equation:

0.60 m/s * m = -9 kg m/s

Dividing both sides of the equation by 0.60 m/s, we get:

m = -9 kg m/s / 0.60 m/s

m = -15 kg

However, a negative mass does not make physical sense. Therefore, there may be an error in the given information or the calculations. Please double-check the values and equations provided.

This problem has been solved

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