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describe, explain and write equations for the reactions of theelements in Period 3 with oxygen and for the reactions of theseoxides with water

Question

Describe, explain and write equations for the reactions of the elements in Period 3 with oxygen and for the reactions of these oxides with water.

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Solution

Sure, let's go through the reactions of the elements in Period 3 with oxygen and their oxides with water.

  1. Sodium (Na): Sodium reacts vigorously with oxygen to form sodium oxide. Equation: 4Na + O2 → 2Na2O Sodium oxide reacts with water to form sodium hydroxide. Equation: Na2O + H2O → 2NaOH

  2. Magnesium (Mg): Magnesium burns in oxygen with a bright white light to form magnesium oxide. Equation: 2Mg + O2 → 2MgO Magnesium oxide reacts with water to form magnesium hydroxide. Equation: MgO + H2O → Mg(OH)2

  3. Aluminum (Al): Aluminum reacts with oxygen to form aluminum oxide. Equation: 4Al + 3O2 → 2Al2O3 Aluminum oxide is amphoteric, meaning it can react with both acids and bases. However, it does not react with water.

  4. Silicon (Si): Silicon reacts with oxygen to form silicon dioxide. Equation: Si + O2 → SiO2 Silicon dioxide is insoluble in water and does not react with it.

  5. Phosphorus (P): Phosphorus reacts with oxygen to form phosphorus pentoxide. Equation: P4 + 5O2 → P4O10 Phosphorus pentoxide reacts with water to form phosphoric acid. Equation: P4O10 + 6H2O → 4H3PO4

  6. Sulfur (S): Sulfur reacts with oxygen to form sulfur dioxide. Equation: S + O2 → SO2 Sulfur dioxide reacts with water to form sulfurous acid. Equation: SO2 + H2O → H2SO3

  7. Chlorine (Cl): Chlorine reacts with oxygen to form dichlorine heptoxide. Equation: 3Cl2 + 7O2 → 2Cl2O7 Dichlorine heptoxide reacts with water to form perchloric acid. Equation: Cl2O7 + H2O → 2HClO4

  8. Argon (Ar): Argon is a noble gas and does not react with oxygen or water.

Please note that some of these reactions require specific conditions (like heat or pressure) to occur.

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