If the sum of three consecutive even numbers is 44 more than the average of these numbers, then the largest of these numbers is?202422None of these

Let's solve this step by step:

Step 1: Let's assume the three consecutive even numbers are x, x+2, and x+4.

Step 2: According to the problem, the sum of these numbers is 44 more than their average. We can write this as:

x + (x+2) + (x+4) = 3x/3 + 44

Step 3: Simplifying the equation, we get:

3x + 6 = x + 44

Step 4: Solving for x, we get:

2x = 38

x = 19

Step 5: But x must be an even number, so there seems to be a mistake. Let's go back and check our work.

Step 6: The mistake is in step 2. The average of the numbers should be (3x + 6) / 3, not 3x / 3. Let's correct this:

x + (x+2) + (x+4) = ((3x + 6) / 3) + 44

Step 7: Simplifying, we get:

3x + 6 = x + 2 + 44

Step 8: Solving for x, we get:

2x = 40

x = 20

Step 9: So the three consecutive even numbers are 20, 22, and 24. Therefore, the largest of these numbers is 24.