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Solve for the variable. Determine if there is one solution, infinitely many solutions, or no solution.-20d – 15 = -5(4d + 3)

Question

Solve for the variable. Determine if there is one solution, infinitely many solutions, or no solution.

−20d–15=−5(4d+3)-20d – 15 = -5(4d + 3)

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Solution

1. Break Down the Problem

We need to solve the equation: −20d−15=−5(4d+3) -20d - 15 = -5(4d + 3) First, we'll simplify the right side of the equation.

2. Relevant Concepts

To simplify, we can distribute −5-5 on the right side: −5(4d+3)=−5×4d−5×3=−20d−15 -5(4d + 3) = -5 \times 4d - 5 \times 3 = -20d - 15 Now we have: −20d−15=−20d−15 -20d - 15 = -20d - 15

3. Analysis and Detail

Next, let's analyze the equation:

  1. When we move all terms to one side, we have: −20d−15+20d+15=0 -20d - 15 + 20d + 15 = 0
  2. Simplifying, we see that: 0=0 0 = 0 This indicates that the original equation holds true for any value of dd.

4. Verify and Summarize

Since the equation simplifies to 0=00 = 0, there are infinitely many solutions because the left side and the right side are identical for all values of dd.

Final Answer

There are infinitely many solutions for the equation −20d−15=−5(4d+3)-20d - 15 = -5(4d + 3).

This problem has been solved

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