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Solve for the variable. Determine if there is one solution, infinitely many solutions, or no solution.-20d – 15 = -5(4d + 3)

Question

Solve for the variable. Determine if there is one solution, infinitely many solutions, or no solution.

20d15=5(4d+3)-20d – 15 = -5(4d + 3)

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Solution

1. Break Down the Problem

We need to solve the equation: 20d15=5(4d+3) -20d - 15 = -5(4d + 3) First, we'll simplify the right side of the equation.

2. Relevant Concepts

To simplify, we can distribute 5-5 on the right side: 5(4d+3)=5×4d5×3=20d15 -5(4d + 3) = -5 \times 4d - 5 \times 3 = -20d - 15 Now we have: 20d15=20d15 -20d - 15 = -20d - 15

3. Analysis and Detail

Next, let's analyze the equation:

  1. When we move all terms to one side, we have: 20d15+20d+15=0 -20d - 15 + 20d + 15 = 0
  2. Simplifying, we see that: 0=0 0 = 0 This indicates that the original equation holds true for any value of dd.

4. Verify and Summarize

Since the equation simplifies to 0=00 = 0, there are infinitely many solutions because the left side and the right side are identical for all values of dd.

Final Answer

There are infinitely many solutions for the equation 20d15=5(4d+3)-20d - 15 = -5(4d + 3).

This problem has been solved

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