Which of the following is an invalid specifier for the printf statement?Group of answer choices%4c%10b%6d%8.2d%10.2e
Question
Which of the following is an invalid specifier for the printf statement?
Group of answer choices
%4c
%10b
%6d
%8.2d
%10.2e
Solution
The invalid specifier for the printf statement among the given options is %10b.
In C programming, the printf statement uses format specifiers to determine the type of data to be printed. Here's a brief explanation of each specifier in the options:
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%4c: This is a valid specifier. It prints a character. The number 4 specifies the minimum field width for the printed character.
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%10b: This is an invalid specifier. 'b' is not a recognized format specifier in C.
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%6d: This is a valid specifier. It prints an integer. The number 6 specifies the minimum field width for the printed integer.
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%8.2d: This is a valid specifier. It prints an integer. The number 8 specifies the minimum field width and the number 2 specifies the precision.
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%10.2e: This is a valid specifier. It prints a floating-point number in scientific notation. The number 10 specifies the minimum field width and the number 2 specifies the number of digits after the decimal point.
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